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In triangle ABC, b=7cm, c=10 cm and angle A=30 degree, find the area of a  triangle ABC. ​ ANS:-                                                                          ​ AREA = ½*(product of adjacent sides)*sin α ​ Where ​ 1. P  is the product of any two  adjacent sides of  a triangle  ​ 2.α is the angle  between the considered adjacent sides      ​ ​ NOW,  We have; ​ AREA= ½*7*10*sin 30° ​ =½*7*10*½ ​ =70/4            ​  =17.5 sq. cm ​ NOTE: Further queries can be asked   over comment section .                                                         ​ ​ ​ ​   ...