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TO PROVE:Sec^4A – tan^4A = 1 + 2tan^2A


TO PROVE:     Sec4A – tan4A = 1 + 2tan2A

Solution:

   L.H.S= sec4A – tan4A

             = (sec2A – tan2A)(sec2A + tan2A)

             =    1 ( sec2 A +  tan2A)                                

             =   sec2 A + tan2 A

             =    1 + tan2 A + tan2 A

             =    1 + 2tan2 A

             = R.H.S

Hence,proved


                                  😁😁   BE HAPPY  😁😁

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