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In triangle ABC, b=7cm, c=10 cm and angle A=30 degree, find the area of a triangle ABC. ​

In triangle ABC, b=7cm, c=10 cm and angle A=30 degree, find the area of a triangle ABC. ​

ANS:-                                                                         ​

AREA = ½*(product of adjacent sides)*sin α​

Where​

1. P  is the product of any two  adjacent sides of  a triangle ​

2.α is the angle between the considered adjacent sides     ​

​

NOW,  We have;​

AREA= ½*7*10*sin 30°​

=½*7*10*½​

=70/4           ​

 =17.5 sq. cm​


NOTE: Further queries can be asked  over comment section .


   

                                                   

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